Title: CMAT 2025 Slot 1 Paper - Indian Game Solutions
Introduction:
The CMAT (Common Management Admission Test) 2025 Slot 1 paper included questions related to Indian games, which are an integral part of our cultural heritage. Here, we provide solutions to some of the questions that might have appeared in the paper.
Question 1:
Identify the following Indian games:
Kho Kho
Kabaddi
Carrom
Ludo
Answer:
Kho Kho: Kho Kho is a traditional Indian sport that involves a seeker and three runners. The seeker has to tag the runners, who can only run in a circular path.
Kabaddi: Kabaddi is a popular team sport played in India, characterized by players from one team running into the opposing team's court, singing a rhyme, and trying to tag opponents while avoiding being tackled.
Carrom: Carrom is a traditional Indian indoor game played on a square board with four corner pockets. The objective is to score points by pocketing discs into the pockets.
Ludo: Ludo is an ancient Indian board game, believed to be the precursor to modern games like Pachisi and Backgammon. It is played on a cross-shaped board with pawns and dice.
Question 2:
Explain the rules of the Indian game of Kho Kho.
Answer:
Kho Kho rules are as follows:
The game is played on a circular track with a diameter of 13 meters (42 feet).
There are three runners and one seeker.
The seeker starts at the center of the circle and tags the runners, who must run in a clockwise direction around the circle.
If a runner is tagged, they are out and must sit out for the remainder of the round.
The game is divided into rounds, and the objective is to tag all three runners before they complete a full circle.
If the seeker is tackled, they are out and the round is over.
The team that tags all three runners in a round wins the game.
Question 3:
Describe the history of the Indian game of Kabaddi.
Answer:
Kabaddi has a rich history that dates back thousands of years. It is believed to have originated in the Indus Valley Civilization around 5000 years ago. Over time, the game evolved and spread across the Indian subcontinent. It became a popular sport during the Mughal era and was even mentioned in ancient Indian texts. Kabaddi was introduced to the Olympics in the 1936 Berlin Games as a demonstration sport, and it has since gained international recognition.
Question 4:
What are the different versions of the Indian game of Carrom?
Answer:
There are several versions of the Indian game of Carrom, including:
Standard Carrom: This is the most common version played in India, where players aim to pocket discs into the corner pockets on a square board.
International Carrom: This version is similar to standard carrom but with a few differences, such as the use of a coin to indicate the lead player and a larger board.
Table Carrom: A smaller version of carrom, played on a table rather than a floor, which is more suitable for indoor play.
Mini Carrom: A compact version of carrom, ideal for small spaces, with a smaller board and fewer discs.
Conclusion:
The CMAT 2025 Slot 1 paper tested candidates' knowledge of Indian games, showcasing their cultural awareness and understanding of traditional sports. The solutions provided here should help candidates who are preparing for similar questions in future exams.
Title: CMAT 2025 Slot 1 Paper: Solution to Game-Based Problems
Problem 1 (Logical Reasoning):
In a strategic board game, 5 players (P1–P5) are divided into two teams: Team Red (3 players) and Team Blue (2 players). Each team must select a unique strategy from three options: Strategy A, B, or C. The probability that exactly two teams choose Strategy A, one team chooses Strategy B, and the remaining team chooses Strategy C is ( \frac{5}{81} ). What is the probability that a player is assigned to Team Red?
Solution:
Total Possible Team Assignments:
There are ( \binom{5}{3} = 10 ) ways to assign 3 players to Team Red and 2 to Team Blue.
Each team independently selects a strategy. With 3 strategies, the total strategy combinations are ( 3 \times 3 = 9 ).
Total possible outcomes: ( 10 \times 9 = 90 ).
Favorable Outcomes:
We need exactly 2 teams to choose Strategy A, 1 team Strategy B, and 1 team Strategy C.
However, since there are only two teams (Red and Blue), the problem may imply a misinterpretation. Assume the question intends strategies per player instead. Adjusting the problem:
Each player independently selects a strategy (A, B, or C).
Probability of exactly 2 players choosing A, 1 choosing B, and 2 choosing C:
[
\frac{\binom{5}{2} \cdot \binom{3}{1} \cdot \binom{2}{2}}{3^5} = \frac{30}{243} = \frac{10}{81}.
]
Given the problem states ( \frac{5}{81} ), revise assumptions: Perhaps teams select strategies, not players.
Team Red (3 players) and Team Blue (2 players) each choose one strategy.
Probability of Team Red choosing A, Team Blue choosing B, and the remaining strategy C:
[
\frac{1}{3} \times \frac{1}{3} \times \frac{1}{1} = \frac{1}{9}.
]
However, this does not align with ( \frac{5}{81} ). Re-examining, the correct setup involves permutations of team strategies:
Total strategy assignments: ( 3^2 = 9 ) (each team picks a strategy).
Favorable cases: Assign A, B, C to the two teams (permutations: ( 3! = 6 )).
Probability: ( \frac{6}{9} = \frac{2}{3} ), which still conflicts.
Conclusion: The problem likely contains ambiguities. Assuming the intended question is about player strategies with adjusted probabilities:
Let the probability of a player choosing Strategy A be ( p ), B be ( q ), and C be ( r ).
Given ( 2p + q + 2r = \frac{5}{81} \times 3^5 ), and ( p + q + r = 1 ).
Solving with symmetry (( q = r )):
[
2p + 3q = \frac{5}{81} \times 243 = 15 \quad \text{and} \quad p + 2q = 1.
]
Solving: ( p = \frac{1}{3} ), ( q = \frac{1}{3} ).
Probability of being in Team Red:
Since teams are randomly assigned, the probability is ( \frac{3}{5} ).
Final Answer:
The probability that a player is assigned to Team Red is ( \boxed{\dfrac{3}{5}} ).
Problem 2 (Data Interpretation):
The table below shows the number of players in a game tournament across three rounds. Round 1 had 120 players, Round 2 had 90, and Round 3 had 60. Each round eliminates 20% of the remaining players. How many players advance to the next round in Round 2, given that 10 players dropped out due to disqualification?
Round
Total Players
Eliminated (Percentage)
Dropped (Absolute)
1
120
20%
–
2
90
20%
10
3
60
–
–
Solution:
Round 1 to Round 2:
Eliminated: ( 120 \times 0.2 = 24 ).
Players remaining: ( 120 - 24 = 96 ).
However, the table shows Round 2 started with 90 players. This discrepancy suggests external eliminations (e.g., dropouts).
Adjusting for Round 2:
Total players entering Round 2: 90.
Eliminated via disqualification: 10.
Players remaining after Round 2: ( 90 - 10 = 80 ).
Eliminated via competition: ( 80 \times 0.2 = 16 ).
Players advancing to Round 3: ( 80 - 16 = 64 ).
Final Answer:
( \boxed{64} ) players advance to Round 3.
Key Takeaways:
Clarify ambiguities in game rules and data.
Use combinatorial probability and systematic elimination logic for problem-solving.
Practice interpreting tables with contextual adjustments.
|
